Optimal. Leaf size=28 \[ \frac{\cos ^8(a+b x)}{b}-\frac{4 \cos ^6(a+b x)}{3 b} \]
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Rubi [A] time = 0.0565491, antiderivative size = 28, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 3, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.15, Rules used = {4287, 2565, 14} \[ \frac{\cos ^8(a+b x)}{b}-\frac{4 \cos ^6(a+b x)}{3 b} \]
Antiderivative was successfully verified.
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Rule 4287
Rule 2565
Rule 14
Rubi steps
\begin{align*} \int \cos ^2(a+b x) \sin ^3(2 a+2 b x) \, dx &=8 \int \cos ^5(a+b x) \sin ^3(a+b x) \, dx\\ &=-\frac{8 \operatorname{Subst}\left (\int x^5 \left (1-x^2\right ) \, dx,x,\cos (a+b x)\right )}{b}\\ &=-\frac{8 \operatorname{Subst}\left (\int \left (x^5-x^7\right ) \, dx,x,\cos (a+b x)\right )}{b}\\ &=-\frac{4 \cos ^6(a+b x)}{3 b}+\frac{\cos ^8(a+b x)}{b}\\ \end{align*}
Mathematica [A] time = 0.122361, size = 48, normalized size = 1.71 \[ \frac{-72 \cos (2 (a+b x))-12 \cos (4 (a+b x))+8 \cos (6 (a+b x))+3 \cos (8 (a+b x))}{384 b} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.017, size = 58, normalized size = 2.1 \begin{align*} -{\frac{3\,\cos \left ( 2\,bx+2\,a \right ) }{16\,b}}-{\frac{\cos \left ( 4\,bx+4\,a \right ) }{32\,b}}+{\frac{\cos \left ( 6\,bx+6\,a \right ) }{48\,b}}+{\frac{\cos \left ( 8\,bx+8\,a \right ) }{128\,b}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.11039, size = 68, normalized size = 2.43 \begin{align*} \frac{3 \, \cos \left (8 \, b x + 8 \, a\right ) + 8 \, \cos \left (6 \, b x + 6 \, a\right ) - 12 \, \cos \left (4 \, b x + 4 \, a\right ) - 72 \, \cos \left (2 \, b x + 2 \, a\right )}{384 \, b} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 0.492864, size = 61, normalized size = 2.18 \begin{align*} \frac{3 \, \cos \left (b x + a\right )^{8} - 4 \, \cos \left (b x + a\right )^{6}}{3 \, b} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 174.245, size = 359, normalized size = 12.82 \begin{align*} \begin{cases} - \frac{3 x \sin ^{2}{\left (a + b x \right )} \sin ^{3}{\left (2 a + 2 b x \right )}}{16} - \frac{3 x \sin ^{2}{\left (a + b x \right )} \sin{\left (2 a + 2 b x \right )} \cos ^{2}{\left (2 a + 2 b x \right )}}{16} - \frac{3 x \sin{\left (a + b x \right )} \sin ^{2}{\left (2 a + 2 b x \right )} \cos{\left (a + b x \right )} \cos{\left (2 a + 2 b x \right )}}{8} - \frac{3 x \sin{\left (a + b x \right )} \cos{\left (a + b x \right )} \cos ^{3}{\left (2 a + 2 b x \right )}}{8} + \frac{3 x \sin ^{3}{\left (2 a + 2 b x \right )} \cos ^{2}{\left (a + b x \right )}}{16} + \frac{3 x \sin{\left (2 a + 2 b x \right )} \cos ^{2}{\left (a + b x \right )} \cos ^{2}{\left (2 a + 2 b x \right )}}{16} - \frac{\sin ^{2}{\left (a + b x \right )} \cos ^{3}{\left (2 a + 2 b x \right )}}{96 b} - \frac{3 \sin{\left (a + b x \right )} \sin ^{3}{\left (2 a + 2 b x \right )} \cos{\left (a + b x \right )}}{16 b} - \frac{\sin{\left (a + b x \right )} \sin{\left (2 a + 2 b x \right )} \cos{\left (a + b x \right )} \cos ^{2}{\left (2 a + 2 b x \right )}}{8 b} - \frac{\sin ^{2}{\left (2 a + 2 b x \right )} \cos ^{2}{\left (a + b x \right )} \cos{\left (2 a + 2 b x \right )}}{2 b} - \frac{31 \cos ^{2}{\left (a + b x \right )} \cos ^{3}{\left (2 a + 2 b x \right )}}{96 b} & \text{for}\: b \neq 0 \\x \sin ^{3}{\left (2 a \right )} \cos ^{2}{\left (a \right )} & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.23138, size = 77, normalized size = 2.75 \begin{align*} \frac{\cos \left (8 \, b x + 8 \, a\right )}{128 \, b} + \frac{\cos \left (6 \, b x + 6 \, a\right )}{48 \, b} - \frac{\cos \left (4 \, b x + 4 \, a\right )}{32 \, b} - \frac{3 \, \cos \left (2 \, b x + 2 \, a\right )}{16 \, b} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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